Answer
A cikin hatimin injina, igiyar igiyar ruwa dole ne ta kula da matsi na fuska daidai. Preload $P$ yana kula da tsayin da aka shigar $L_i$. Saboda tarin juriya a cikin mahalli, gland, da fuskar carbon, $ L_i $ na iya bambanta sosai ($ ΔL $). Tun da $P = k \cdot (L_0 - L_i)$, kowane saɓani a cikin $L_i$ yana haifar da bambancin $P$. Idan $k$ yayi girma, ko da ƙaramin $ΔL$ na iya sa hatimin ya yoyo (ƙananan $P$) ko sawa da wuri (babban $P$). Masu ƙira sukan zaɓi maɓuɓɓugan Crest-to-Crest tare da ƙimar bazara mai 'lalata' (ƙananan $k$) kan doguwar tafiya don rage azancin ɗaukar nauyi zuwa waɗannan jurewar masana'anta.