Official Answer
Answer
In a Shear Failure, the ring itself is cut into two pieces along its circumference. ພື້ນຜິວຄວາມລົ້ມເຫຼວຈະປາກົດເປັນເງົາ, ບໍລິເວນທີ່ຖືກໄຟໄຫມ້ຕາມມາດ້ວຍການກະດູກຫັກ rough, ສະແດງໃຫ້ເຫັນວ່າຄວາມກົດດັນ shear $\tau = P / (\pi D t)$ ເກີນຄວາມແຮງ shear ຂອງວັດສະດຸ ($~0.6 \times UTS$). Groove Yielding, however, is characterized by the groove wall being pushed back or 'rolled' over. The ring may remain intact but will be 'dished' or deformed. Diagnosis is simple: if the groove is still sharp and within tolerance but the ring is sheared, the ring material was insufficient. If the groove is deformed and the ring 'popped out', the housing material was too soft or the groove was too shallow for the applied load.
