Official Answer
Answer
Ku mpeta zo hanze, imbaraga za centrifugal zikunda kwagura impeta, birashoboka kuyikura muri ruhago. Umuvuduko ntarengwa wemewe $ V $ muri RPM ugenwa na $ V = \ sqrt {\ frac {4 \ cdot E \ cdot g \ cdot (d_n - d_g)} {0.0132 \ cdot \ rho \ cdot D_m ^ 5 \ cdot (D_o - D_i)}} $, aho $ d_n $ $ bitagira aho bibogamiye. Niba umuvuduko wo gusaba urenze agaciro, impeta igomba kuba yarakozwe hamwe n '' kwifungisha '. Iyi miterere igizwe na tab hamwe nu mwanya urinda muburyo bwo gukingira impeta kwaguka kurenza diameter ya groove, bigatuma RPMs zisumba izindi cyane mumashini yihuta yihuta nka mashini ya turbine.
