Official Answer
Answer
The installation stress $\sigma_i$ of an internal ring occurs when it is compressed to fit into the bore. ມັນຖືກຄິດໄລ່ເປັນ $\sigma_i = \frac{E \cdot b \cdot (D_g - D_f)}{D_m^2}$, ເຊິ່ງ $D_g$ ແມ່ນເສັ້ນຜ່າສູນກາງຂອງຮ່ອງ ແລະ $D_f$ ແມ່ນເສັ້ນຜ່າສູນກາງຟຣີ. If the radial wall $b$ is too large, the stress during installation can exceed the material's elastic limit, resulting in 'permanent set'. This means the ring won't 'snap back' into the groove, leading to a loose fit. Conversely, a $b$ that is too small reduces the thrust capacity. ການອອກແບບຕ້ອງດຸ່ນດ່ຽງເຫຼົ່ານີ້ໂດຍໃຊ້ 'ອັດຕາສ່ວນການຂະຫຍາຍ', ຮັບປະກັນ $\sigma_i < 0.8 \cdot S_y$ ສໍາລັບການຕິດຕັ້ງແບບຊ້ໍາກັນ.
