Knowledge Center

Installation & Assembly

Fitting, tooling, removal and system assembly.

278 Published questions
2 Core topics
1:1 Question intake

If the published answers do not match your application, send us your question and our team will review it.

Questions & Answers

Engineer-reviewed questions

Loading questions...

A Reference Answer

Axial vibration can cause a spiral ring to 'float' within the groove if the preload is insufficient. The 'clinging' force is a result of the ring's free diameter being smaller (for a shaft) or larger (for a bore) than the groove diameter. The interference fit creates a radial pressure $p = \frac{2 E I Δ}{R_m^4}$, where $Δ$ is the interference. For high-vibration applications, the interference should be maximized within the limits of the material's elastic strain during installation. Additionally, a 'zero-clearance' groove width—where the ring thickness $t$ is nearly equal to the groove width—can be used to eliminate axial 'shucking.'

A Reference Answer

The radial wall $w$ of a spiral ring determines the 'protrusion' of the ring above the shaft or below the bore. This is the 'retaining shoulder' that actually holds the mating part. Designers must ensure that the mating part has a contact face that fully covers the ring's radial wall to avoid point-loading the inner edge. However, there must also be clearance between the ID of the mating part (for a shaft ring) and the OD of the ring. If the mating part's ID is too small, it will hit the ring's 'ears' or 'turns,' preventing proper assembly. Spiral rings are preferred here because they have no 'ears' or lugs, providing 360-degree contact.

A Reference Answer

A chamfer or radius on the retained part (e.g., a bearing) reduces the effective contact area with the spiral ring and introduces a radial force component that promotes 'dishing.' The maximum allowable chamfer $c$ is typically limited to $50\%$ of the ring's radial wall $w$. If the chamfer is too large, the load is applied further from the groove wall, increasing the moment arm and leading to premature ring roll-out. In such cases, a 'backup washer' with a sharp corner must be placed between the chamfered component and the retaining ring to ensure purely axial load transmission.

A Reference Answer

For high-volume production, manual installation of spiral rings with pliers or screwdrivers is slow and risks scratching the shaft. A tapered mandrel or 'plug' allows the ring to be gradually expanded as it is pushed axially. This ensures the expansion is uniform around the circumference, preventing localized yielding. The taper angle should be shallow (typically $15^{\circ}$ to $20^{\circ}$) to minimize the force required. Once the ring reaches the groove, it 'snaps' into place. This method is easily automated and ensures the ring's planarity is maintained, which is vital for the performance of the 'clinging' force.

A Reference Answer

'Rolling' or 'dishing' of a spiral ring occurs when the thrust load causes the ring to twist, leading to premature ejection. To prevent this, the groove must have a sharp corner (maximum radius of $10\%$ of material thickness $t$) and a sufficiently deep wall. The 'Groove Deformation' load $P_g$ is often the limiting factor rather than the 'Ring Shear' load $P_r$. $P_g$ is calculated using $P_g = \frac{D \pi G S_y}{K}$, where $G$ is groove depth, $D$ is shaft/bore diameter, $S_y$ is the yield strength of the groove material, and $K$ is a safety factor (usually 2.0). If the housing is a soft material like aluminum, a wider groove and thicker ring are mandatory.

A Reference Answer

Shim ends, also known as 'flat ends,' are produced by flattening the last half-wave on each end of a multi-turn spring. This creates a $360^{\circ}$ contact surface rather than point contact at the peaks. This is critical for applications where the spring must provide uniform pressure on a seal or a bearing race. While shim ends increase the solid height $H_s$ by $2t$, they significantly reduce the 'tipping' moment and ensure that the load is transmitted axially. The spring rate calculation must be adjusted because the shim ends act as inactive turns, reducing the effective number of active waves.

A Reference Answer

Tall Crest-to-Crest wave springs (where $L_{free}/D_m > 1.5$) are susceptible to buckling or 'snaking' when compressed. The radial wall thickness $b$ contributes to the lateral stiffness. To prevent buckling, the spring should be guided either by a shaft or in a bore. The clearance should be minimal but sufficient to allow for the diameter expansion during compression. If no guide is possible, the engineer must increase the radial width $b$ to improve the moment of inertia $I = \frac{b t^3}{12}$ relative to the axial direction, effectively increasing the critical buckling load $P_{cr}$.

A Reference Answer

Nesting involves stacking multiple single-turn wave springs in parallel to increase the load capacity (load scales by the number of springs). The primary risk is friction between the layers, which introduces hysteresis in the load-deflection curve and generates heat during cyclic operation. Misalignment of the wave peaks between nested layers can also cause localized stress spikes and non-uniform loading. To address this, nested springs should ideally be manufactured as a single continuous 'interlaced' or multi-turn nested spring where the coils are produced together, ensuring perfect synchronization of the waves.

A Reference Answer

When a wave spring is compressed, its diameter expands slightly. If installed in a bore, the clearance between the spring OD and the bore ID must accommodate the expansion $\Delta D \approx 0.02 \times (f/N)$ per wave to prevent binding. If installed on a shaft, the ID must have sufficient clearance to avoid 'clinging' during deflection. Furthermore, the seating surfaces must be flat and hard; soft housing materials like aluminum may suffer from 'fretting' or 'brinelling' due to the concentrated point loads at the wave peaks, necessitating the use of a hardened shim washer.

A Reference Answer

Load consistency in wave springs is highly sensitive to the installed work height $H_w$. Because the spring rate $k$ is linear in its design range, any variation in the housing or shaft axial dimensions directly affects the load $P = k(L_{free} - H_w)$. In a Crest-to-Crest assembly, cumulative tolerances of the waves and the alignment of peaks can introduce a 'shimming' effect. Engineers must specify a 'load at work height' rather than just a free height to ensure the assembly maintains the required preload, especially in bearing preloading where a deviation of $\pm 10\%$ in load can significantly alter bearing life.

A Reference Answer

Unlike stamped rings with holes for pliers, spiral rings are removed by prying the end out of the groove. A 'removal notch' is a small cutout at one end of the ring that allows a screwdriver or dental pick to get behind the wire. In some high-performance applications, 'scallops' or multiple notches are added to allow for removal in tight spaces where the primary end might be inaccessible. For assemblies that require frequent maintenance (e.g., aerospace gearboxes), the inclusion of a removal notch is a critical 'design for service' feature. Without it, the ring may be impossible to remove without damaging the shaft or the groove, leading to costly component replacements.

A Reference Answer

'Oil canning' or 'snap-through' is a form of elastic instability that occurs in single-turn wave springs when the ratio of the wave height $h$ to the material thickness $t$ is too high. If the spring is compressed, it may reach a point where it 'snaps' into an inverted shape or a flattened state with a sudden drop in load. This is mathematically similar to the buckling of a shallow arch. To avoid this, designers should keep the $h/t$ ratio within a range where the spring rate remains positive. If the rate $dk/df$ becomes negative, the spring is unstable. This is a critical failure mode in switch mechanisms where a positive tactile 'click' is required, but it is a failure in structural preload applications.

A Reference Answer

The edge margin is the distance between the groove and the end of the shaft or bore. If the edge margin is too small, the housing material will fail in shear or 'blow out' when the ring is loaded axially. The required edge margin $z$ is typically calculated as $z = \frac{3 \cdot P}{\pi \cdot D \cdot \sigma_y}$, where $P$ is the thrust load and $\sigma_y$ is the yield strength of the housing material. A general guideline for steel housings is an edge margin of $3 \cdot d$ (three times the groove depth), while for aluminum housings, $4 \cdot d$ or $5 \cdot d$ is recommended. Failure to provide sufficient edge margin will lead to a catastrophic failure of the assembly, even if the retaining ring itself is intact.

A Reference Answer

Measuring the work height $H_w$ requires a precision load tester. The spring is compressed to the specified work height $H_w$, and the resulting force $P$ is recorded. It is incorrect to measure the free height $L_f$ and then subtract the deflection, as the spring rate is often slightly non-linear in the first $20\%$ and last $20\%$ of the stroke. The load should be measured during the 'compression' stroke to avoid the influence of hysteresis. For high-precision springs, the 'shimmed' ends must be perfectly flat against the tester's plates. Any deviation in the parallelism of the testing plates will result in an inaccurate load reading due to uneven wave compression.

A Reference Answer

Spiral retaining rings are coiled from flat wire and typically have two or three turns, which provides a $360^{\circ}$ retaining surface with no lugs or 'ears'. In contrast, stamped circlips have large lugs for pliers that can interfere with other components. For installation in blind holes (internal rings), spiral rings can be 'wound' into the groove. One end is started in the groove, and the rest of the ring is spiraled in manually or with a simple tool. This is particularly advantageous when there is no access for traditional circlip pliers. Furthermore, the absence of lugs means the spiral ring has a lower profile and a more uniform radial cross-section, which improves the balance in high-speed rotating assemblies.

A Reference Answer

Eccentric loading occurs when the load $P$ is not applied uniformly over the circumference of the wave spring, often due to a tilted plunger or an off-center housing. This creates a non-uniform stress distribution: $\sigma(\theta) = \frac{P}{A} + \frac{M \cdot y}{I}$, where $M$ is the moment caused by the eccentricity. Some waves will be compressed more than others, leading to localized yielding and a decrease in the overall spring rate. In hydraulic valves, this can cause the spool to stick or leak because the spring force is not balanced. To prevent this, the spring must be guided by either a shaft on the ID or a bore on the OD, ensuring that the spring remains centered and the load is axial.

A Reference Answer

The groove radius is the small fillet at the bottom corner of the groove. While a radius is necessary to reduce stress concentrations in the shaft or housing, an excessive radius significantly reduces the ring's thrust capacity. A large radius allows the ring to 'climb' the wall of the groove under axial load, inducing a dishing moment. The standard design rule is that the maximum groove radius $R_{max}$ should be no larger than $0.1 \cdot d$, where $d$ is the groove depth. If a larger radius is required for fatigue life of the shaft, a custom ring with a chamfer on its inner edge may be necessary to ensure the ring sits flat against the groove wall, maintaining the intended shear plane.

A Reference Answer

Nested wave springs consist of multiple turns coiled in parallel, essentially acting as a single spring with a thickness $T = n \cdot t$, where $n$ is the number of turns. The alignment of the waves is critical; they must be perfectly synchronized to act as a parallel spring system. If the waves are misaligned, the spring will not nest properly, leading to uneven loading and potential interference between turns. The manufacturing process uses a 'continuous filament' coiling technique to ensure the waves are perfectly phased. During installation, care must be taken to avoid twisting the spring, as any axial distortion can cause 'wave-mismatch', resulting in a spring rate that fluctuates unpredictably as the layers slide against each other.

A Reference Answer

Over-expanding a spiral retaining ring occurs when the ring is stretched beyond its elastic limit during installation over a shaft or into a bore. This results in permanent plastic deformation, meaning the ring will not return to its original 'clinging' diameter, leading to a loose fit in the groove. The maximum installation diameter $D_{max}$ should be calculated such that the fiber stress does not exceed the yield strength $\sigma_y$. Prevention involves using a tapered mandrel or a sleeve for installation, which controls the expansion to a specific limit. Additionally, the formula for the stress during expansion is $S = \frac{E \cdot t \cdot (D_s - D_i)}{(D_m^2)}$, where $D_s$ is the shaft diameter and $D_i$ is the ring's free inside diameter. If $S > \sigma_y$, the ring is compromised.

A Reference Answer

Wave springs expand radially as they are compressed from their free height to their work height. This expansion is defined by the formula $\Delta D \approx 0.02 \cdot \frac{(L_f - L_w) \cdot t}{N}$, where $L_f$ is the free height and $L_w$ is the work height. If the spring is installed in a bore with insufficient clearance, the outside diameter (OD) will bind against the housing walls. This binding creates excessive friction, which manifests as a higher-than-calculated spring rate and causes localized wear or 'fretting'. For a Crest-to-Crest spring, it is vital to calculate the maximum OD at the solid height $H_s$ to ensure it remains below the minimum bore diameter $D_b$ throughout the entire operating range.

No matching questions

TOP